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25a^2+5a-2=0
a = 25; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·25·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-15}{2*25}=\frac{-20}{50} =-2/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+15}{2*25}=\frac{10}{50} =1/5 $
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